What is the d/(dy)((x)((5x+2y)^8)) ?

The d/(dy)((x)((5x+2y)^8)) is 16x(5x+2y)^7

What is the first d/(dy)((x)((5x+2y)^8)) ?

The first d/(dy)((x)((5x+2y)^8)) is 16x(5x+2y)^7

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\frac{d}{d y} ((x) ((5 x + 2 y)^{8}))

16 x (5 x + 2 y)^{7}

Solution steps

\frac{d}{d y} ((x) ((5 x + 2 y)^{8}))

Treat

x

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= x \frac{d}{d y} ((5 x + 2 y)^{8})

Apply the chain rule:

8 (5 x + 2 y)^{7} \frac{d}{d y} (5 x + 2 y)

= 8 (5 x + 2 y)^{7} \frac{d}{d y} (5 x + 2 y)

\frac{d}{d y} (5 x + 2 y) = 2

= x \cdot 8 (5 x + 2 y)^{7} \cdot 2

Simplify

= 16 x (5 x + 2 y)^{7}

(2 i) (3 i^{2}) (5)

\frac{x ^{4} - x ^{3} - 13 x ^{2} + 2 x + 6}{( x + 3 ) ( x + 4 )}

\frac{( ( 2 p + q ) ^{3} - ( q - 2 p ) ^{3} )}{2 p}

(\frac{1}{x ^{2}} + y^{2}) (x d y - y d x)

- \frac{1}{( z - 1 ) ( z - 2 )}

What is the d/(dy)((x)((5x+2y)^8)) ?
The d/(dy)((x)((5x+2y)^8)) is 16x(5x+2y)^7
What is the first d/(dy)((x)((5x+2y)^8)) ?
The first d/(dy)((x)((5x+2y)^8)) is 16x(5x+2y)^7