What is expand-sin(x)(1+e^y) ?

The solution to expand-sin(x)(1+e^y) is -sin(x)-e^ysin(x)

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expand-sin(x)(1+e^y)

expand

- sin (x) (1 + e^{y})

- sin (x) - e^{y} sin (x)

Solution steps

- sin (x) (1 + e^{y})

Apply the distributive law:

a (b + c) = ab + a c

a = - sin (x), b = 1, c = e^{y}

= - sin (x) \cdot 1 + (- sin (x)) e^{y}

Apply minus-plus rules

+ (- a) = - a

= - 1 \cdot sin (x) - e^{y} sin (x)

Multiply:

1 \cdot sin (x) = sin (x)

= - sin (x) - e^{y} sin (x)

\frac{\frac{d}{d x} ( x ( x ^{3} - 1 ) )}{x + 1}

\frac{( ( x + 2 ) ^{\frac{1}{3}} - 2 ^{\frac{1}{3}} )}{x}

\frac{1 - e ^{- 3 π s}}{s ( s ^{2} + 1 )}

\frac{16}{( 2 x + 1 ) ^{2}}

\frac{2 \cdot ( - x ^{4} + ( h + x ) ^{4} )}{h}

What is expand-sin(x)(1+e^y) ?
The solution to expand-sin(x)(1+e^y) is -sin(x)-e^ysin(x)