What is expand ,(x-1)(x-2)(x-4) ?

The solution to expand ,(x-1)(x-2)(x-4) is x^3-7x^2+14x-8

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expand ,(x-1)(x-2)(x-4)

expand

(x - 1) (x - 2) (x - 4)

x^{3} - 7 x^{2} + 14 x - 8

Solution steps

(x - 1) (x - 2) (x - 4)

Expand

(x - 1) (x - 2) (x - 4) : (x^{2} - 3 x + 2) (x - 4)

= (x^{2} - 3 x + 2) (x - 4)

Distribute parentheses

= x^{2} x + x^{2} (- 4) - 3 xx - 3 x (- 4) + 2 x + 2 (- 4)

Simplify

x^{2} x + x^{2} (- 4) - 3 xx - 3 x (- 4) + 2 x + 2 (- 4) : x^{3} - 7 x^{2} + 14 x - 8

= x^{3} - 7 x^{2} + 14 x - 8

(p + Δ p + 1)^{2}

\frac{( \frac{3 x}{2} )}{( \frac{3}{x} + 2 )}

(x + 5) + (x + 5) + (3 x - 2)

(v + 1) (v d y + y d v)

\frac{1}{( s + 7 ) ( s - 5 ) ( s + 12 )}

What is expand ,(x-1)(x-2)(x-4) ?
The solution to expand ,(x-1)(x-2)(x-4) is x^3-7x^2+14x-8