What is expand ((-3x-2)h+3x+2)/h ?

The solution to expand ((-3x-2)h+3x+2)/h is -3x-2+(3x)/h+2/h

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expand ((-3x-2)h+3x+2)/h

expand

\frac{( - 3 x - 2 ) h + 3 x + 2}{h}

- 3 x - 2 + \frac{3 x}{h} + \frac{2}{h}

Solution steps

\frac{( - 3 x - 2 ) h + 3 x + 2}{h}

Expand

(- 3 x - 2) h + 3 x + 2 : - 3 x h - 2 h + 3 x + 2

= \frac{- 3 x h - 2 h + 3 x + 2}{h}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{- 3 x h - 2 h + 3 x + 2}{h} = - \frac{3 x h}{h} - \frac{2 h}{h} + \frac{3 x}{h} + \frac{2}{h}

= - \frac{3 x h}{h} - \frac{2 h}{h} + \frac{3 x}{h} + \frac{2}{h}

Cancel

\frac{3 x h}{h} : 3 x

= - 3 x - \frac{2 h}{h} + \frac{3 x}{h} + \frac{2}{h}

Cancel

\frac{2 h}{h} : 2

= - 3 x - 2 + \frac{3 x}{h} + \frac{2}{h}

\frac{( b ^{2} + a ^{2} ) ( b + a )}{2 ( b ^{2} + ba + a ^{2} )}

f (x y) 5 (2 x + y - 3)^{2}

\frac{d}{d x} ((1 - x) cos (x)) + 2 x^{2} sin (x)

(- 12 y - 4 z = 16) 4

\frac{3 ( a + h )}{( a + h ) - 2}

What is expand ((-3x-2)h+3x+2)/h ?
The solution to expand ((-3x-2)h+3x+2)/h is -3x-2+(3x)/h+2/h