What is expand (2y^3(y-1))/((2y-1)) ?

The solution to expand (2y^3(y-1))/((2y-1)) is (2y^4-2y^3)/(2y-1)

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expand (2y^3(y-1))/((2y-1))

expand

\frac{2 y ^{3} ( y - 1 )}{( 2 y - 1 )}

\frac{2 y ^{4} - 2 y ^{3}}{2 y - 1}

Solution steps

\frac{2 y ^{3} ( y - 1 )}{2 y - 1}

Expand

2 y^{3} (y - 1) : 2 y^{4} - 2 y^{3}

= \frac{2 y ^{4} - 2 y ^{3}}{2 y - 1}

\frac{e ^{- 4 x} + 3 x}{( x ) ( x ^{2} + 1 )}

π (3 r + 8 s)^{2} \cdot (12 r + 32 s)

(f \circ g) 3 (- x + 7) - 2

, (s + 1) (\frac{s}{2} + 1) (\frac{s}{3} + 1)

(\frac{- x ^{2} + 8 x + 3}{4} - \frac{sin ( \frac{π x}{3} )}{2}) \cdot x

What is expand (2y^3(y-1))/((2y-1)) ?
The solution to expand (2y^3(y-1))/((2y-1)) is (2y^4-2y^3)/(2y-1)