What is expand 1/(((x-b)(x-c))) ?

The solution to expand 1/(((x-b)(x-c))) is 1/(x^2-cx-bx+bc)

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expand 1/(((x-b)(x-c)))

expand

\frac{1}{( ( x - b ) ( x - c ) )}

\frac{1}{x ^{2} - c x - b x + b c}

Solution steps

\frac{1}{( x - b ) ( x - c )}

Expand

(x - b) (x - c) : x^{2} - c x - b x + b c

= \frac{1}{x ^{2} - c x - b x + b c}

(e^{2 x} + 2 e^{2 x} x)^{2}

\frac{7 ( 3 a - 1 )}{b ( 5 a + 1 )}

4 (0.5 f - 0.25 = 6 + f)

(e^{x} sin (2 x)) (e^{x} cos (2 x) + 2 e^{x} sin (2 x))

- \frac{4}{( x - 1 ) ^{2}}

What is expand 1/(((x-b)(x-c))) ?
The solution to expand 1/(((x-b)(x-c))) is 1/(x^2-cx-bx+bc)