What is expand ((3x^3+2))/(((x-1)(x^2+9))) ?

The solution to expand ((3x^3+2))/(((x-1)(x^2+9))) is (3x^3+2)/(x^3+9x-x^2-9)

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expand ((3x^3+2))/(((x-1)(x^2+9)))

expand

\frac{( 3 x ^{3} + 2 )}{( ( x - 1 ) ( x ^{2} + 9 ) )}

\frac{3 x ^{3} + 2}{x ^{3} + 9 x - x ^{2} - 9}

Solution steps

\frac{3 x ^{3} + 2}{( x - 1 ) ( x ^{2} + 9 )}

Expand

(x - 1) (x^{2} + 9) : x^{3} + 9 x - x^{2} - 9

= \frac{3 x ^{3} + 2}{x ^{3} + 9 x - x ^{2} - 9}

\frac{x ^{2} + 2 x + 1}{4 x}

(e^{x} + \frac{1}{u})^{2}

\frac{d ^{2}}{d x ^{2}} ((y) (5 x^{3} + sin (x)))

((- 1.1, 3.7) + (- 5, 1.5)) (- 2.9)

(9 x - 2 y = 11) (5)

What is expand ((3x^3+2))/(((x-1)(x^2+9))) ?
The solution to expand ((3x^3+2))/(((x-1)(x^2+9))) is (3x^3+2)/(x^3+9x-x^2-9)