What is e^{pi(b-in)}-e^{-pi(b-in)} ?

The solution to e^{pi(b-in)}-e^{-pi(b-in)} is (-1)^ne^{pib}-(-1)^ne^{-pib}

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simplify e^{pi(b-in)}-e^{-pi(b-in)}

simplify

e^{π (b - in)} - e^{- π (b - in)}

(- 1)^{n} e^{πb} - (- 1)^{n} e^{- πb}

Solution steps

e^{π (b - in)} - e^{- π (b - in)}

e^{π (b - in)} = (- 1)^{n} e^{πb}

e^{- π (b - in)} = (- 1)^{n} e^{- πb}

= (- 1)^{n} e^{πb} - (- 1)^{n} e^{- πb}

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\frac{2}{9} x^{3} y^{2} - \frac{4}{3} x y^{3}

What is e^{pi(b-in)}-e^{-pi(b-in)} ?
The solution to e^{pi(b-in)}-e^{-pi(b-in)} is (-1)^ne^{pib}-(-1)^ne^{-pib}