What is expand (((x+1)(x+3)(2x-3)))/(((x+5)(x-3))) ?

The solution to expand (((x+1)(x+3)(2x-3)))/(((x+5)(x-3))) is (2x^3+5x^2-6x-9)/(x^2+2x-15)

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expand (((x+1)(x+3)(2x-3)))/(((x+5)(x-3)))

expand

\frac{( ( x + 1 ) ( x + 3 ) ( 2 x - 3 ) )}{( ( x + 5 ) ( x - 3 ) )}

\frac{2 x ^{3} + 5 x ^{2} - 6 x - 9}{x ^{2} + 2 x - 15}

Solution steps

\frac{( x + 1 ) ( x + 3 ) ( 2 x - 3 )}{( x + 5 ) ( x - 3 )}

Expand

(x + 5) (x - 3) : x^{2} + 2 x - 15

= \frac{( x + 1 ) ( x + 3 ) ( 2 x - 3 )}{x ^{2} + 2 x - 15}

Expand

(x + 1) (x + 3) (2 x - 3) : 2 x^{3} + 5 x^{2} - 6 x - 9

= \frac{2 x ^{3} + 5 x ^{2} - 6 x - 9}{x ^{2} + 2 x - 15}

\frac{230 ( 1 7 ^{- r + 1} - 1 )}{- r + 1}

\frac{x - 1}{x ( x + 2 )}

d x (5 t - 2)^{4}

x - (x^{2} + 4 x + 3) \cdot e^{- x}

(t^{2} - t + 5) H (t - 2)

What is expand (((x+1)(x+3)(2x-3)))/(((x+5)(x-3))) ?
The solution to expand (((x+1)(x+3)(2x-3)))/(((x+5)(x-3))) is (2x^3+5x^2-6x-9)/(x^2+2x-15)