What is expand (t^2-t+5)\H(t-2) ?

The solution to expand (t^2-t+5)\H(t-2) is t^2\H(t-2)-t\H(t-2)+5\H(t-2)

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expand (t^2-t+5)\H(t-2)

expand

(t^{2} - t + 5) H (t - 2)

t^{2} H (t - 2) - t H (t - 2) + 5 H (t - 2)

Solution steps

(t^{2} - t + 5) H (t - 2)

= H (t - 2) (t^{2} - t + 5)

Distribute parentheses

= H (t - 2) t^{2} + H (t - 2) (- t) + H (t - 2) \cdot 5

Apply minus-plus rules

+ (- a) = - a

= t^{2} H (t - 2) - t H (t - 2) + 5 H (t - 2)

(3 y + x^{4}) d x - x d y

\frac{5 x - 4}{3 x ( x - 1 )}

\frac{\partial}{\partial x} ((z) (x^{2} + z^{2}))

\frac{- s ^{2} + 4 s + 21}{( s ^{2} - 4 s + 29 ) ^{2}}

1 + \frac{4 e ^{2 x}}{( e ^{2 x} - 1 ) ^{2}}

What is expand (t^2-t+5)\H(t-2) ?
The solution to expand (t^2-t+5)\H(t-2) is t^2\H(t-2)-t\H(t-2)+5\H(t-2)