What is (\partial)/(\partial x)((z)(x^2+z^2)) ?

The answer to (\partial)/(\partial x)((z)(x^2+z^2)) is 2zx

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(\partial)/(\partial x)((z)(x^2+z^2))

\frac{\partial}{\partial x} ((z) (x^{2} + z^{2}))

2 z x

Solution steps

\frac{\partial}{\partial x} ((z) (x^{2} + z^{2}))

Treat

z

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= z \frac{\partial}{\partial x} (x^{2} + z^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= z (\frac{\partial}{\partial x} (x^{2}) + \frac{\partial}{\partial x} (z^{2}))

\frac{\partial}{\partial x} (x^{2}) = 2 x

\frac{\partial}{\partial x} (z^{2}) = 0

= z (2 x + 0)

Simplify

= 2 z x

\frac{- s ^{2} + 4 s + 21}{( s ^{2} - 4 s + 29 ) ^{2}}

1 + \frac{4 e ^{2 x}}{( e ^{2 x} - 1 ) ^{2}}

A (- 2, - 5) y B (3, - 1)

49 - x^{2} \cdot 25 - x^{2}

\frac{( x - 4 ) ^{4} + ( x - 3 ) ^{6} + 10}{( x - 2 ) ( x - 3 )}

What is (\partial)/(\partial x)((z)(x^2+z^2)) ?
The answer to (\partial)/(\partial x)((z)(x^2+z^2)) is 2zx