What is expand e^{(x^2-3)(x+4)} ?

The solution to expand e^{(x^2-3)(x+4)} is e^{x^3+4x^2-3x-12}

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expand e^{(x^2-3)(x+4)}

expand

e^{(x^{2} - 3) (x + 4)}

e^{x^{3} + 4 x^{2} - 3 x - 12}

Solution steps

e^{(x^{2} - 3) (x + 4)}

Expand

(x^{2} - 3) (x + 4) : x^{3} + 4 x^{2} - 3 x - 12

= e^{x^{3} + 4 x^{2} - 3 x - 12}

(2 π + 16) \cdot 10

\frac{3 x ( x ^{2} - 5 )}{x ^{2} - 1}

\frac{40 ( 4 cos ( 40 t ) - sin ( 40 t ) )}{17}

\frac{( - x ^{2} cos ( x ) + 2 ( x sin ( x ) + cos ( x ) ) )}{x}

(- 2.9 e^{- (0.4 x - 2.4)} + 12.4)^{2}

What is expand e^{(x^2-3)(x+4)} ?
The solution to expand e^{(x^2-3)(x+4)} is e^{x^3+4x^2-3x-12}