What is (d^2)/(dx^2)((y)(-4x^5+4)) ?

The answer to (d^2)/(dx^2)((y)(-4x^5+4)) is -4x^5(d^2y)/(dx^2)-40x^4(dy)/(dx)-80x^3y+4(d^2y)/(dx^2)

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(d^2)/(dx^2)((y)(-4x^5+4))

\frac{d ^{2}}{d x ^{2}} ((y) (- 4 x^{5} + 4))

- 4 x^{5} \frac{d ^{2} y}{d x ^{2}} - 40 x^{4} \frac{d y}{d x} - 80 x^{3} y + 4 \frac{d ^{2} y}{d x ^{2}}

Solution steps

\frac{d ^{2}}{d x ^{2}} ((y) (- 4 x^{5} + 4))

\frac{d}{d x} (y (- 4 x^{5} + 4)) = \frac{d y}{d x} (- 4 x^{5} + 4) - 20 x^{4} y

= \frac{d}{d x} (\frac{d y}{d x} (- 4 x^{5} + 4) - 20 x^{4} y)

\frac{d}{d x} (\frac{d y}{d x} (- 4 x^{5} + 4) - 20 x^{4} y) = - 4 x^{5} \frac{d ^{2} y}{d x ^{2}} - 40 x^{4} \frac{d y}{d x} - 80 x^{3} y + 4 \frac{d ^{2} y}{d x ^{2}}

= - 4 x^{5} \frac{d ^{2} y}{d x ^{2}} - 40 x^{4} \frac{d y}{d x} - 80 x^{3} y + 4 \frac{d ^{2} y}{d x ^{2}}

1 5^{2}

\frac{8}{13 ( s ^{2} + 4 s + 13 )}

\frac{( 20 + x ^{2} ) ^{2}}{9}

(3 x^{2} + y) d x + (x^{2} y - x) d y

(\frac{y - 1}{2})^{4}

What is (d^2)/(dx^2)((y)(-4x^5+4)) ?
The answer to (d^2)/(dx^2)((y)(-4x^5+4)) is -4x^5(d^2y)/(dx^2)-40x^4(dy)/(dx)-80x^3y+4(d^2y)/(dx^2)