What are the solutions to the equation (x+5)(x-4)=(x+5) ?

The solutions to the equation (x+5)(x-4)=(x+5) are x=5,x=-5

Find the zeros of (x+5)(x-4)=(x+5)

The zeros of (x+5)(x-4)=(x+5) are x=5,x=-5

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(x + 5) (x - 4) = (x + 5)

x = 5, x = - 5

Solution steps

(x + 5) (x - 4) = (x + 5)

Expand

(x + 5) (x - 4) : x^{2} + x - 20

x^{2} + x - 20 = x + 5

Move

20

to the right side

x^{2} + x = x + 25

Move

x

to the left side

x^{2} = 25

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 25, x = - 25

25 = 5

- 25 = - 5

x = 5, x = - 5

7 = 4 x - 5

9 x^{2} + 63 x + 90 \leq 0

(\frac{1}{2})^{2} + (\frac{1}{2})^{2}

\frac{7}{3 - 7 i}

64 x^{2} + 16 x + 1 = 0

What are the solutions to the equation (x+5)(x-4)=(x+5) ?
The solutions to the equation (x+5)(x-4)=(x+5) are x=5,x=-5
Find the zeros of (x+5)(x-4)=(x+5)
The zeros of (x+5)(x-4)=(x+5) are x=5,x=-5