What is the d/(dθ)((t)(sqrt(2)-cos(θ))) ?

The d/(dθ)((t)(sqrt(2)-cos(θ))) is tsin(θ)

What is the first d/(dθ)((t)(sqrt(2)-cos(θ))) ?

The first d/(dθ)((t)(sqrt(2)-cos(θ))) is tsin(θ)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d θ} ((t) (2 - cos (θ)))

t sin (θ)

Solution steps

\frac{d}{d θ} ((t) (2 - cos (θ)))

Treat

t

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= t \frac{d}{d θ} (2 - cos (θ))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= t (\frac{d}{d θ} (2) - \frac{d}{d θ} (cos (θ)))

\frac{d}{d θ} (2) = 0

\frac{d}{d θ} (cos (θ)) = - sin (θ)

= t (0 - (- sin (θ)))

Simplify

= t sin (θ)

(2 + 3 x + 4 x^{2})^{5}

25 (2 - 3) 2 + 3

4 y^{2} e^{y^{2} - x^{2}} (1 + x^{2} + y^{2})

\frac{7 ( 2 x + 1 )}{3 x - 5}

- \frac{4}{( x - 1 ) ^{3}}

What is the d/(dθ)((t)(sqrt(2)-cos(θ))) ?
The d/(dθ)((t)(sqrt(2)-cos(θ))) is tsin(θ)
What is the first d/(dθ)((t)(sqrt(2)-cos(θ))) ?
The first d/(dθ)((t)(sqrt(2)-cos(θ))) is tsin(θ)