What is expand (f\circ g)(3-log_{10}(x^2-25)) ?

The solution to expand (f\circ g)(3-log_{10}(x^2-25)) is 3\circ fg-\circ fglog_{10}(x^2-25)

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expand (f\circ g)(3-log_{10}(x^2-25))

expand

(f \circ g) (3 - lo g_{10} (x^{2} - 25))

3 \circ f g - \circ f g lo g_{10} (x^{2} - 25)

Solution steps

(f \circ g) (3 - lo g_{10} (x^{2} - 25))

= (\circ f g) (3 - lo g_{10} (x^{2} - 25))

Apply the distributive law:

a (b - c) = ab - a c

a = (f \circ g), b = 3, c = lo g_{10} (x^{2} - 25)

= (f \circ g) \cdot 3 - (f \circ g) lo g_{10} (x^{2} - 25)

= 3 (\circ f g) - lo g_{10} (x^{2} - 25) (\circ f g)

Remove parentheses:

(a) = a

= 3 \circ f g - \circ f g lo g_{10} (x^{2} - 25)

1000 0^{2} - 999 9^{2}

cos (x) d x + (1 + \frac{2}{( y )}) sin (x) d y

- 4 \cdot ((8, - 4) - (3, 12))

(- 2) (3 x - 2 y = 9)

What is expand (f\circ g)(3-log_{10}(x^2-25)) ?
The solution to expand (f\circ g)(3-log_{10}(x^2-25)) is 3\circ fg-\circ fglog_{10}(x^2-25)