What is expand (7v^2-4v-3)(6v-2^') ?

The solution to expand (7v^2-4v-3)(6v-2^') is 42v^3-7*2^'v^2-24v^2+4*2^'v-18v+3*2^'

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expand (7v^2-4v-3)(6v-2^')

expand

(7 v^{2} - 4 v - 3) (6 v - 2^{^{'}})

42 v^{3} - 7 \cdot 2^{'} v^{2} - 24 v^{2} + 4 \cdot 2^{'} v - 18 v + 3 \cdot 2^{'}

Solution steps

(7 v^{2} - 4 v - 3) (6 v - 2^{^{'}})

Distribute parentheses

= 7 v^{2} \cdot 6 v + 7 v^{2} (- 2^{^{^{'}}}) + (- 4 v) \cdot 6 v + (- 4 v) (- 2^{^{^{'}}}) + (- 3) \cdot 6 v + (- 3) (- 2^{^{^{'}}})

Apply minus-plus rules

+ (- a) = - a, (- a) (- b) = ab

= 7 \cdot 6 v^{2} v - 7 \cdot 2^{^{^{'}}} v^{2} - 4 \cdot 6 vv + 4 \cdot 2^{^{^{'}}} v - 3 \cdot 6 v + 3 \cdot 2^{^{^{'}}}

Simplify

7 \cdot 6 v^{2} v - 7 \cdot 2^{^{'}} v^{2} - 4 \cdot 6 vv + 4 \cdot 2^{^{'}} v - 3 \cdot 6 v + 3 \cdot 2^{^{'}} : 42 v^{3} - 7 \cdot 2^{^{'}} v^{2} - 24 v^{2} + 4 \cdot 2^{^{'}} v - 18 v + 3 \cdot 2^{^{'}}

= 42 v^{3} - 7 \cdot 2^{^{'}} v^{2} - 24 v^{2} + 4 \cdot 2^{^{'}} v - 18 v + 3 \cdot 2^{^{'}}

(5 x - 8 q^{2})^{2 (m - 2)}

\frac{2}{( ( s + 2 ) \cdot ( s + 1 ) )}

\frac{2}{4 + 2}

(\frac{2 x + ( 1 )}{( 4 x )})^{(20)}

What is expand (7v^2-4v-3)(6v-2^') ?
The solution to expand (7v^2-4v-3)(6v-2^') is 42v^3-7*2^'v^2-24v^2+4*2^'v-18v+3*2^'