What is expand [(x+1)(x-1)]^2 ?

The solution to expand [(x+1)(x-1)]^2 is x^4-2x^2+1

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expand [(x+1)(x-1)]^2

expand

[(x + 1) (x - 1)]^{2}

x^{4} - 2 x^{2} + 1

Solution steps

((x + 1) (x - 1))^{2}

Expand

(x + 1) (x - 1) : x^{2} - 1

= (x^{2} - 1)^{2}

Apply Perfect Square Formula:

(a - b)^{2} = a^{2} - 2 ab + b^{2}

a = x^{2}, b = 1

= (x^{2})^{2} - 2 x^{2} \cdot 1 + 1^{2}

Simplify

(x^{2})^{2} - 2 x^{2} \cdot 1 + 1^{2} : x^{4} - 2 x^{2} + 1

= x^{4} - 2 x^{2} + 1

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\frac{5 ( s + 2 ) ( 2 s + 3 )}{2 s ^{2} + 8 s + 10}

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(\frac{cos ( x )}{x} - sin (ln (x)))^{2}

What is expand [(x+1)(x-1)]^2 ?
The solution to expand [(x+1)(x-1)]^2 is x^4-2x^2+1