What is (\partial)/(\partial x)((y)(y+1)(y-1)) ?

The answer to (\partial)/(\partial x)((y)(y+1)(y-1)) is 0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial x)((y)(y+1)(y-1))

\frac{\partial}{\partial x} ((y) (y + 1) (y - 1))

0

Solution steps

\frac{\partial}{\partial x} ((y) (y + 1) (y - 1))

Treat

y

as a constant

Derivative of a constant:

\frac{d}{d x} (a) = 0

= 0

((x^{2} + y^{2}) - x) d x + (y) d y

\frac{d ^{2}}{d x ^{2}} ((y) (12 x^{2} - 12 x + 10))

(1 + y^{2} + x y^{2}) d x

\frac{2659}{12 , 3} \cdot (1 + 0.17638 \cdot \frac{12 , 3}{10 , 3})

\frac{50 x}{( 20 x + 5 )}

What is (\partial)/(\partial x)((y)(y+1)(y-1)) ?
The answer to (\partial)/(\partial x)((y)(y+1)(y-1)) is 0