What is expand ((x-2)(x+2)(x-3))/((x+4)(x^2-5x+12)) ?

The solution to expand ((x-2)(x+2)(x-3))/((x+4)(x^2-5x+12)) is (x^3-3x^2-4x+12)/(x^3-x^2-8x+48)

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expand ((x-2)(x+2)(x-3))/((x+4)(x^2-5x+12))

expand

\frac{( x - 2 ) ( x + 2 ) ( x - 3 )}{( x + 4 ) ( x ^{2} - 5 x + 12 )}

\frac{x ^{3} - 3 x ^{2} - 4 x + 12}{x ^{3} - x ^{2} - 8 x + 48}

Solution steps

\frac{( x - 2 ) ( x + 2 ) ( x - 3 )}{( x + 4 ) ( x ^{2} - 5 x + 12 )}

Expand

(x + 4) (x^{2} - 5 x + 12) : x^{3} - x^{2} - 8 x + 48

= \frac{( x - 2 ) ( x + 2 ) ( x - 3 )}{x ^{3} - x ^{2} - 8 x + 48}

Expand

(x - 2) (x + 2) (x - 3) : x^{3} - 3 x^{2} - 4 x + 12

= \frac{x ^{3} - 3 x ^{2} - 4 x + 12}{x ^{3} - x ^{2} - 8 x + 48}

\frac{n ( n - 1 )}{n !}

(a, b) (3, - 4)

\frac{π}{s ^{2} + π ^{2} ( s ^{2} + 1 )}

t e^{u (t - 1)}

so l v e (x^{2} - 4.5 x + 1 = 0)

What is expand ((x-2)(x+2)(x-3))/((x+4)(x^2-5x+12)) ?
The solution to expand ((x-2)(x+2)(x-3))/((x+4)(x^2-5x+12)) is (x^3-3x^2-4x+12)/(x^3-x^2-8x+48)