What is expand (n(n-1))/(n!) ?

The solution to expand (n(n-1))/(n!) is (n^2)/(n!)-n/(n!)

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expand (n(n-1))/(n!)

expand

\frac{n ( n - 1 )}{n !}

\frac{n ^{2}}{n !} - \frac{n}{n !}

Solution steps

\frac{n ( n - 1 )}{n !}

Expand

n (n - 1) : n^{2} - n

= \frac{n ^{2} - n}{n !}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{n ^{2} - n}{n !} = \frac{n ^{2}}{n !} - \frac{n}{n !}

= \frac{n ^{2}}{n !} - \frac{n}{n !}

(a, b) (3, - 4)

\frac{π}{s ^{2} + π ^{2} ( s ^{2} + 1 )}

t e^{u (t - 1)}

so l v e (x^{2} - 4.5 x + 1 = 0)

\frac{72 x ^{2} - 24}{( x ^{2} + 1 ) ^{3}}

What is expand (n(n-1))/(n!) ?
The solution to expand (n(n-1))/(n!) is (n^2)/(n!)-n/(n!)