What is expand (x-5)(x+5=(x-1)) ?

The solution to expand (x-5)(x+5=(x-1)) is x^2+5x=x-1

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expand (x-5)(x+5=(x-1))

expand

(x - 5) (x + 5 = (x - 1))

x^{2} + 5 x = x - 1

Solution steps

(x - 5) (x + 5 = (x - 1))

Apply FOIL method:

(a + b) (c + d) = a c + a d + b c + b d

a = x, b = - 5, c = x, d = 5 = (x - 1)

xx + x \cdot 5 = (x - 1) + (- 5) x + (- 5) \cdot 5 = (x - 1)

Apply minus-plus rules

+ (- a) = - a

xx + 5 x = (x - 1) - 5 x - 5 \cdot 5 = (x - 1)

Simplify

xx + 5 x = (x - 1) - 5 x - 5 \cdot 5 = (x - 1) : x^{2} + 5 x = x - 1

x^{2} + 5 x = x - 1

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What is expand (x-5)(x+5=(x-1)) ?
The solution to expand (x-5)(x+5=(x-1)) is x^2+5x=x-1