What is expand (1-ln(x^2+1))^2 ?

The solution to expand (1-ln(x^2+1))^2 is 1-2ln(x^2+1)+ln^2(x^2+1)

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expand (1-ln(x^2+1))^2

expand

(1 - ln (x^{2} + 1))^{2}

1 - 2 ln (x^{2} + 1) + ln^{2} (x^{2} + 1)

Solution steps

(1 - ln (x^{2} + 1))^{2}

Apply Perfect Square Formula:

(a - b)^{2} = a^{2} - 2 ab + b^{2}

a = 1, b = ln (x^{2} + 1)

= 1^{2} - 2 \cdot 1 \cdot ln (x^{2} + 1) + ln^{2} (x^{2} + 1)

Simplify

1^{2} - 2 \cdot 1 \cdot ln (x^{2} + 1) + ln^{2} (x^{2} + 1) : 1 - 2 ln (x^{2} + 1) + ln^{2} (x^{2} + 1)

= 1 - 2 ln (x^{2} + 1) + ln^{2} (x^{2} + 1)

\frac{x ( l s + a )}{l s}

\frac{x - 3}{x ( x ^{2} + 24 )}

2 e (e + 5)

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LU (t - 4) (2 - t^{2}) + 2 e - π t + cos (3 t) - t^{3}

What is expand (1-ln(x^2+1))^2 ?
The solution to expand (1-ln(x^2+1))^2 is 1-2ln(x^2+1)+ln^2(x^2+1)