What is expand e^x(3sin(2x)-2cos(x)) ?

The solution to expand e^x(3sin(2x)-2cos(x)) is 3e^xsin(2x)-2e^xcos(x)

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expand e^x(3sin(2x)-2cos(x))

expand

e^{x} (3 sin (2 x) - 2 cos (x))

3 e^{x} sin (2 x) - 2 e^{x} cos (x)

Solution steps

e^{x} (3 sin (2 x) - 2 cos (x))

Apply the distributive law:

a (b - c) = ab - a c

a = e^{x}, b = 3 sin (2 x), c = 2 cos (x)

= e^{x} \cdot 3 sin (2 x) - e^{x} \cdot 2 cos (x)

= 3 e^{x} sin (2 x) - 2 e^{x} cos (x)

(X - \frac{π}{2}) \cdot (X - π)

\frac{243 ( - 3 x ^{4} + 243 )}{( x ^{4} + 243 ) ^{2}}

(xxx = - 32) 3 (2) 3

(n + 2)! (n + 2) - 1

\frac{24}{5 24}

What is expand e^x(3sin(2x)-2cos(x)) ?
The solution to expand e^x(3sin(2x)-2cos(x)) is 3e^xsin(2x)-2e^xcos(x)