What is expand ((x-3)(x+1))/((x-2)(x-1)) ?

The solution to expand ((x-3)(x+1))/((x-2)(x-1)) is (x^2-2x-3)/(x^2-3x+2)

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expand ((x-3)(x+1))/((x-2)(x-1))

expand

\frac{( x - 3 ) ( x + 1 )}{( x - 2 ) ( x - 1 )}

\frac{x ^{2} - 2 x - 3}{x ^{2} - 3 x + 2}

Solution steps

\frac{( x - 3 ) ( x + 1 )}{( x - 2 ) ( x - 1 )}

Expand

(x - 2) (x - 1) : x^{2} - 3 x + 2

= \frac{( x - 3 ) ( x + 1 )}{x ^{2} - 3 x + 2}

Expand

(x - 3) (x + 1) : x^{2} - 2 x - 3

= \frac{x ^{2} - 2 x - 3}{x ^{2} - 3 x + 2}

e^{(- 2 (s))} (\frac{1}{s ^{2}} + \frac{3}{s}) - s

(- \frac{y ^{2}}{3} - 3 x^{2} = - 3) (- \frac{1}{3})

\frac{3}{( t + 1 ) ^{5}}

- \frac{1}{4} e^{- 8 t} + \frac{3}{49} (- 7 e^{- 7 t} t - e^{- 7 t})

3.924 x + 1.596 (e^{- 2.5 x} - 1)

What is expand ((x-3)(x+1))/((x-2)(x-1)) ?
The solution to expand ((x-3)(x+1))/((x-2)(x-1)) is (x^2-2x-3)/(x^2-3x+2)