What is expand (pi(x+6)(36-x^2))/3 ?

The solution to expand (pi(x+6)(36-x^2))/3 is -(pix^3)/3-2pix^2+12pix+72pi

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expand (pi(x+6)(36-x^2))/3

expand

\frac{π ( x + 6 ) ( 36 - x ^{2} )}{3}

- \frac{π x ^{3}}{3} - 2 π x^{2} + 12 π x + 72 π

Solution steps

\frac{π ( x + 6 ) ( 36 - x ^{2} )}{3}

Expand

π (x + 6) (36 - x^{2}) : 36 π x - π x^{3} + 216 π - 6 π x^{2}

= \frac{36 π x - π x ^{3} + 216 π - 6 π x ^{2}}{3}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{36 π x - π x ^{3} + 216 π - 6 π x ^{2}}{3} = \frac{36 π x}{3} - \frac{π x ^{3}}{3} + \frac{216 π}{3} - \frac{6 π x ^{2}}{3}

= \frac{36 π x}{3} - \frac{π x ^{3}}{3} + \frac{216 π}{3} - \frac{6 π x ^{2}}{3}

Divide the numbers:

\frac{36}{3} = 12

= 12 π x - \frac{π x ^{3}}{3} + \frac{216 π}{3} - \frac{6 π x ^{2}}{3}

Divide the numbers:

\frac{216}{3} = 72

= 12 π x - \frac{π x ^{3}}{3} + 72 π - \frac{6 π x ^{2}}{3}

Divide the numbers:

\frac{6}{3} = 2

= 12 π x - \frac{π x ^{3}}{3} + 72 π - 2 π x^{2}

Rewrite in standard form

= - \frac{π x ^{3}}{3} - 2 π x^{2} + 12 π x + 72 π

5 \cdot im p u l se (t - 0.4)

4 (2 x^{5} + x^{2} - 10)^{5}

m u lt i pl y (\frac{19}{2} - x) (\frac{19}{2} - x)

(y - \frac{π}{6})^{2}

(t + 9)^{7} d t

What is expand (pi(x+6)(36-x^2))/3 ?
The solution to expand (pi(x+6)(36-x^2))/3 is -(pix^3)/3-2pix^2+12pix+72pi