What is expand (n^{n-1}-1)/((n-1)^2) ?

The solution to expand (n^{n-1}-1)/((n-1)^2) is (n^{n-1}-1)/(n^2-2n+1)

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expand (n^{n-1}-1)/((n-1)^2)

expand

\frac{n ^{n - 1} - 1}{( n - 1 ) ^{2}}

\frac{n ^{n - 1} - 1}{n ^{2} - 2 n + 1}

Solution steps

\frac{n ^{n - 1} - 1}{( n - 1 ) ^{2}}

(n - 1)^{2} = n^{2} - 2 n + 1

= \frac{n ^{n - 1} - 1}{n ^{2} - 2 n + 1}

x \cdot (1 - e^{- l \cdot x})

- \frac{2 ( - 3 x ^{2} - 1 )}{( x ^{2} - 1 ) ^{3}}

(x^{2} + y^{2}) d y - 2 x y d x

6 cos (13 5^{\circ}) - 6 cos (4 5^{\circ})

((x m - x n) 2) d x

What is expand (n^{n-1}-1)/((n-1)^2) ?
The solution to expand (n^{n-1}-1)/((n-1)^2) is (n^{n-1}-1)/(n^2-2n+1)