What is expand ln(x^2-1)(x^2-1) ?

The solution to expand ln(x^2-1)(x^2-1) is x^2ln(x^2-1)-ln(x^2-1)

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expand ln(x^2-1)(x^2-1)

expand

ln (x^{2} - 1) (x^{2} - 1)

x^{2} ln (x^{2} - 1) - ln (x^{2} - 1)

Solution steps

ln (x^{2} - 1) (x^{2} - 1)

Apply the distributive law:

a (b - c) = ab - a c

a = ln (x^{2} - 1), b = x^{2}, c = 1

= ln (x^{2} - 1) x^{2} - ln (x^{2} - 1) \cdot 1

= x^{2} ln (x^{2} - 1) - 1 \cdot ln (x^{2} - 1)

Multiply:

1 \cdot ln (x^{2} - 1) = ln (x^{2} - 1)

= x^{2} ln (x^{2} - 1) - ln (x^{2} - 1)

t^{4} (e^{11 t} + t^{3})

x (5 t + 2) d t

12 (- 2)

e^{x + y} (1 + \frac{d y}{d x})

(vx + v x^{3}) (v d x + x d v)

What is expand ln(x^2-1)(x^2-1) ?
The solution to expand ln(x^2-1)(x^2-1) is x^2ln(x^2-1)-ln(x^2-1)