What is expand (2(5x^2-3x+2))/(x+4) ?

The solution to expand (2(5x^2-3x+2))/(x+4) is (10x^2-6x+4)/(x+4)

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expand (2(5x^2-3x+2))/(x+4)

expand

\frac{2 ( 5 x ^{2} - 3 x + 2 )}{x + 4}

\frac{10 x ^{2} - 6 x + 4}{x + 4}

Solution steps

\frac{2 ( 5 x ^{2} - 3 x + 2 )}{x + 4}

Expand

2 (5 x^{2} - 3 x + 2) : 10 x^{2} - 6 x + 4

= \frac{10 x ^{2} - 6 x + 4}{x + 4}

1 + \frac{e ^{s} ( 1 - e ^{- s} )}{s}

R e (x + i y)^{4}

1 - 6 \cdot (y + 3 = - 23)

\frac{( a + b ) a}{x ( x + z )}

\frac{2 x ( 2 x + 1 )}{( x - 3 ) ( x + 1 )}

What is expand (2(5x^2-3x+2))/(x+4) ?
The solution to expand (2(5x^2-3x+2))/(x+4) is (10x^2-6x+4)/(x+4)