What is expand (8+2x)^{(-1)/3} ?

The solution to expand (8+2x)^{(-1)/3} is 1/((8+2x)^{1/3)}

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expand (8+2x)^{(-1)/3}

expand

(8 + 2 x)^{\frac{- 1}{3}}

\frac{1}{( 8 + 2 x ) ^{\frac{1}{3}}}

Solution steps

(8 + 2 x)^{\frac{- 1}{3}}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

= (8 + 2 x)^{- \frac{1}{3}}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= \frac{1}{( 8 + 2 x ) ^{\frac{1}{3}}}

\frac{2}{( s + 5 ) ^{2} ( s )}

- \frac{5 ( 3 x - 5 )}{2 x + 3}

\frac{5 x ^{6} ( - 6 x tan ( 6 x ) + 7 )}{7 sec ( 6 x )}

3 (x (b f - ce) - y (a f - c d) + z (a e - b d))

\frac{- a + ( - a ^{2} - 4 ( 2 a - 1 ) )}{2}

What is expand (8+2x)^{(-1)/3} ?
The solution to expand (8+2x)^{(-1)/3} is 1/((8+2x)^{1/3)}