What is expand (2ty(y^3-1))/(3(1+t^2)) ?

The solution to expand (2ty(y^3-1))/(3(1+t^2)) is (2ty^4-2ty)/(3+3t^2)

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expand (2ty(y^3-1))/(3(1+t^2))

expand

\frac{2 t y ( y ^{3} - 1 )}{3 ( 1 + t ^{2} )}

\frac{2 t y ^{4} - 2 t y}{3 + 3 t ^{2}}

Solution steps

\frac{2 t y ( y ^{3} - 1 )}{3 ( 1 + t ^{2} )}

Expand

3 (1 + t^{2}) : 3 + 3 t^{2}

= \frac{2 t y ( y ^{3} - 1 )}{3 + 3 t ^{2}}

Expand

2 t y (y^{3} - 1) : 2 t y^{4} - 2 t y

= \frac{2 t y ^{4} - 2 t y}{3 + 3 t ^{2}}

\frac{90}{7 ( 2 x - 7 )}

\frac{4}{3 ( - π + 6 )}

- \frac{23}{( 4 x - 3 ) ^{2}}

\frac{2 x y - y ^{4}}{3 x ^{2}}

6 sin (\frac{2 x + π}{3}) - (33 + 4) cos (2 x)

What is expand (2ty(y^3-1))/(3(1+t^2)) ?
The solution to expand (2ty(y^3-1))/(3(1+t^2)) is (2ty^4-2ty)/(3+3t^2)