What is expand ((3!)/(2!1!))(3/16)^1(4/16)^2 ?

The solution to expand ((3!)/(2!1!))(3/16)^1(4/16)^2 is 9/256

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expand ((3!)/(2!1!))(3/16)^1(4/16)^2

expand

(\frac{3 !}{2 ! 1 !}) (\frac{3}{16})^{1} (\frac{4}{16})^{2}

\frac{9}{256}

Decimal Notation

0.03515625

Solution steps

(\frac{3 !}{2 ! \cdot 1 !}) (\frac{3}{16})^{1} (\frac{4}{16})^{2}

Apply rule

a^{1} = a

(\frac{3}{16})^{1} = \frac{3}{16}

= (\frac{4}{16})^{2} \frac{3}{16} \cdot \frac{3 !}{2 ! \cdot 1 !}

\frac{3 !}{2 ! \cdot 1 !} = \frac{3}{1 !}

= (\frac{4}{16})^{2} \frac{3}{1 !} \cdot \frac{3}{16}

(\frac{4}{16})^{2} = \frac{1}{4 ^{2}}

= \frac{3}{1 !} \cdot \frac{3}{16} \cdot \frac{1}{4 ^{2}}

Multiply fractions:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{3 \cdot 3 \cdot 1}{1 ! \cdot 16 \cdot 4 ^{2}}

Multiply the numbers:

3 \cdot 3 \cdot 1 = 9

= \frac{9}{4 ^{2} \cdot 16 \cdot 1 !}

1! \cdot 16 \cdot 4^{2} = 256

= \frac{9}{256}

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What is expand ((3!)/(2!1!))(3/16)^1(4/16)^2 ?
The solution to expand ((3!)/(2!1!))(3/16)^1(4/16)^2 is 9/256