What is expand 2pi((sqrt(2))/9-1/18) ?

The solution to expand 2pi((sqrt(2))/9-1/18) is (2sqrt(2)pi)/9-pi/9

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand 2pi((sqrt(2))/9-1/18)

expand

2 π (\frac{2}{9} - \frac{1}{18})

\frac{2 2 π}{9} - \frac{π}{9}

Solution steps

2 π (\frac{2}{9} - \frac{1}{18})

Apply the distributive law:

a (b - c) = ab - a c

a = 2 π, b = \frac{2}{9}, c = \frac{1}{18}

= 2 π \frac{2}{9} - 2 π \frac{1}{18}

Simplify

2 π \frac{2}{9} - 2 π \frac{1}{18} : \frac{2 2 π}{9} - \frac{π}{9}

= \frac{2 2 π}{9} - \frac{π}{9}

\frac{1}{( x - 6 ) ^{3}}

\frac{1}{π} [+ 2 - (- 1)^{n} + \frac{π ^{2}}{2} - e^{π}]

P (6, - 2) y Q (- 8, 4)

ln (4 x) \cdot (x^{2} + x)

(1 - ϕ) \frac{d}{d ϕ} (K (ϕ))

What is expand 2pi((sqrt(2))/9-1/18) ?
The solution to expand 2pi((sqrt(2))/9-1/18) is (2sqrt(2)pi)/9-pi/9