What is expand (2x-2x^2-2xh)/(3h(x+h)) ?

The solution to expand (2x-2x^2-2xh)/(3h(x+h)) is (2x-2x^2-2xh)/(3xh+3h^2)

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expand (2x-2x^2-2xh)/(3h(x+h))

expand

\frac{2 x - 2 x ^{2} - 2 x h}{3 h ( x + h )}

\frac{2 x - 2 x ^{2} - 2 x h}{3 x h + 3 h ^{2}}

Solution steps

\frac{2 x - 2 x ^{2} - 2 x h}{3 h ( x + h )}

Expand

3 h (x + h) : 3 x h + 3 h^{2}

= \frac{2 x - 2 x ^{2} - 2 x h}{3 x h + 3 h ^{2}}

\frac{1}{2} - \frac{1}{2} cos^{2} (2 x)

- \frac{3 ( - n - 27 π ^{3} )}{n ^{2}}

\frac{3 ( x ^{2} + 2 x + 6 )}{2}

4 x (x + 10 - 2 (x - 5) = 2^{2} - 4)

(u x^{3} - ln (x)) (x d u + u d x)

What is expand (2x-2x^2-2xh)/(3h(x+h)) ?
The solution to expand (2x-2x^2-2xh)/(3h(x+h)) is (2x-2x^2-2xh)/(3xh+3h^2)