What are the solutions to the equation 3x^2-9=-2x ?

The solutions to the equation 3x^2-9=-2x are x=(-1+2sqrt(7))/3 ,x=-(1+2sqrt(7))/3

Find the zeros of 3x^2-9=-2x

The zeros of 3x^2-9=-2x are x=(-1+2sqrt(7))/3 ,x=-(1+2sqrt(7))/3

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3 x^{2} - 9 = - 2 x

x = \frac{- 1 + 2 7}{3}, x = - \frac{1 + 2 7}{3}

Decimal Notation

x = 1.43050 \dots, x = - 2.09716 \dots

Solution steps

3 x^{2} - 9 = - 2 x

Move

2 x

to the left side

3 x^{2} - 9 + 2 x = 0

Write in the standard form

a x^{2} + b x + c = 0

3 x^{2} + 2 x - 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 3 ( - 9 )}{2 \cdot 3}

2^{2} - 4 \cdot 3 (- 9) = 47

x_{1, 2} = \frac{- 2 \pm 4 7}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 2 + 4 7}{2 \cdot 3}, x_{2} = \frac{- 2 - 4 7}{2 \cdot 3}

x = \frac{- 2 + 4 7}{2 \cdot 3} : \frac{- 1 + 2 7}{3}

x = \frac{- 2 - 4 7}{2 \cdot 3} : - \frac{1 + 2 7}{3}

The solutions to the quadratic equation are:

x = \frac{- 1 + 2 7}{3}, x = - \frac{1 + 2 7}{3}

\frac{9}{- 5} + \frac{- 8}{7}

3 2^{\frac{6}{5}}

- \frac{5}{9} \cdot 4

2 w^{2} + w = 66

What are the solutions to the equation 3x^2-9=-2x ?
The solutions to the equation 3x^2-9=-2x are x=(-1+2sqrt(7))/3 ,x=-(1+2sqrt(7))/3
Find the zeros of 3x^2-9=-2x
The zeros of 3x^2-9=-2x are x=(-1+2sqrt(7))/3 ,x=-(1+2sqrt(7))/3