What is expand (1+2x)^{0.5}(2x)(x^2+1)^{1/3} ?

The solution to expand (1+2x)^{0.5}(2x)(x^2+1)^{1/3} is 2x(1+2x)^{1/2}(x^2+1)^{1/3}

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expand (1+2x)^{0.5}(2x)(x^2+1)^{1/3}

expand

(1 + 2 x)^{0.5} (2 x) (x^{2} + 1)^{\frac{1}{3}}

2 x (1 + 2 x)^{\frac{1}{2}} (x^{2} + 1)^{\frac{1}{3}}

Solution steps

(1 + 2 x)^{\frac{1}{2}} (2 x) (x^{2} + 1)^{\frac{1}{3}}

Remove parentheses:

(a) = a

= (1 + 2 x)^{\frac{1}{2}} \cdot 2 x (x^{2} + 1)^{\frac{1}{3}}

F (0.3) D (y = - 3)

lo g_{7} (w)

\frac{2 x ^{2} - x + 8}{( x ^{2} + 4 ) ^{2}}

\frac{x ^{3} + x ^{2} + 1}{x ( x - 1 ) ( x ^{2} + x + 1 ) ( x ^{2} + 1 ) ^{2}}

\frac{( 0.2 - x )}{( 0.2 + x ) x}

What is expand (1+2x)^{0.5}(2x)(x^2+1)^{1/3} ?
The solution to expand (1+2x)^{0.5}(2x)(x^2+1)^{1/3} is 2x(1+2x)^{1/2}(x^2+1)^{1/3}