What is expand ((3x+2)(2x-1))/((2x-2)(3x+1)) ?

The solution to expand ((3x+2)(2x-1))/((2x-2)(3x+1)) is (6x^2+x-2)/(6x^2-4x-2)

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expand ((3x+2)(2x-1))/((2x-2)(3x+1))

expand

\frac{( 3 x + 2 ) ( 2 x - 1 )}{( 2 x - 2 ) ( 3 x + 1 )}

\frac{6 x ^{2} + x - 2}{6 x ^{2} - 4 x - 2}

Solution steps

\frac{( 3 x + 2 ) ( 2 x - 1 )}{( 2 x - 2 ) ( 3 x + 1 )}

Expand

(2 x - 2) (3 x + 1) : 6 x^{2} - 4 x - 2

= \frac{( 3 x + 2 ) ( 2 x - 1 )}{6 x ^{2} - 4 x - 2}

Expand

(3 x + 2) (2 x - 1) : 6 x^{2} + x - 2

= \frac{6 x ^{2} + x - 2}{6 x ^{2} - 4 x - 2}

0.04 (- 2 e^{- 0.5 t} t - 3 e^{- 0.5 t}) + C

\frac{n ^{2} - n}{2} \cdot \frac{n + 2}{3}

1 + (x^{2} + 1)

\frac{6}{( x + h ) ^{2}}

(x^{2} + y^{2} + 1) d x - 2 x y d y

What is expand ((3x+2)(2x-1))/((2x-2)(3x+1)) ?
The solution to expand ((3x+2)(2x-1))/((2x-2)(3x+1)) is (6x^2+x-2)/(6x^2-4x-2)