What is expand (2(5x^2-3x+2))/(x-4) ?

The solution to expand (2(5x^2-3x+2))/(x-4) is (10x^2-6x+4)/(x-4)

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expand (2(5x^2-3x+2))/(x-4)

expand

\frac{2 ( 5 x ^{2} - 3 x + 2 )}{x - 4}

\frac{10 x ^{2} - 6 x + 4}{x - 4}

Solution steps

\frac{2 ( 5 x ^{2} - 3 x + 2 )}{x - 4}

Expand

2 (5 x^{2} - 3 x + 2) : 10 x^{2} - 6 x + 4

= \frac{10 x ^{2} - 6 x + 4}{x - 4}

\frac{( n + 1 )}{π ( n + 2 )}

\frac{2 s - 14}{( s + 3 ) ^{2}}

\frac{9 x ^{2} - 11}{2 ( x + 3 ) ( 2 x + 1 )}

π (162 + \frac{181}{8})

(5 y - 18) sin (4 9^{\circ})

What is expand (2(5x^2-3x+2))/(x-4) ?
The solution to expand (2(5x^2-3x+2))/(x-4) is (10x^2-6x+4)/(x-4)