What is 1/(x+1)+1/x > 2/(x+2) ?

The solution to 1/(x+1)+1/x > 2/(x+2) is x 0

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1/(x+1)+1/x > 2/(x+2)

\frac{1}{x + 1} + \frac{1}{x} > \frac{2}{x + 2}

x < - 2 or - 1 < x < - \frac{2}{3} or x > 0

Interval Notation

(- \infty, - 2) \cup (- 1, - \frac{2}{3}) \cup (0, \infty)

Decimal Notation

x < - 2 or - 1 < x < - 0.66666 \dots or x > 0

Solution steps

\frac{1}{x + 1} + \frac{1}{x} > \frac{2}{x + 2}

Rewrite in standard form

\frac{3 x + 2}{x ( x + 1 ) ( x + 2 )} > 0

Identify the intervals

x < - 2 or - 1 < x < - \frac{2}{3} or x > 0

\frac{2 - x}{4 - x} \leq 1

100 - x^{2} = 0

(- \frac{t}{3})^{2}

3 (x - 3) = 3 x + 4

n^{2} = 64

What is 1/(x+1)+1/x > 2/(x+2) ?
The solution to 1/(x+1)+1/x > 2/(x+2) is x<-2\lor-1<x<-2/3 \lor x>0