What is expand (8x^3+48x^2+96x+64)/(4x^2+16x+16) ?

The solution to expand (8x^3+48x^2+96x+64)/(4x^2+16x+16) is 2x+4

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expand (8x^3+48x^2+96x+64)/(4x^2+16x+16)

expand

\frac{8 x ^{3} + 48 x ^{2} + 96 x + 64}{4 x ^{2} + 16 x + 16}

2 x + 4

Solution steps

\frac{8 x ^{3} + 48 x ^{2} + 96 x + 64}{4 x ^{2} + 16 x + 16}

Factor

8 x^{3} + 48 x^{2} + 96 x + 64 : 8 (x^{3} + 6 x^{2} + 12 x + 8)

= \frac{8 ( x ^{3} + 6 x ^{2} + 12 x + 8 )}{4 x ^{2} + 16 x + 16}

Factor

4 x^{2} + 16 x + 16 : 4 (x^{2} + 4 x + 4)

= \frac{8 ( x ^{3} + 6 x ^{2} + 12 x + 8 )}{4 ( x ^{2} + 4 x + 4 )}

Divide the numbers:

\frac{8}{4} = 2

= \frac{2 ( x ^{3} + 6 x ^{2} + 12 x + 8 )}{( x ^{2} + 4 x + 4 )}

Remove parentheses:

(a) = a

= \frac{2 ( x ^{3} + 6 x ^{2} + 12 x + 8 )}{x ^{2} + 4 x + 4}

Factor

2 (x^{3} + 6 x^{2} + 12 x + 8) : 2 (x + 2)^{3}

= \frac{2 ( x + 2 ) ^{3}}{x ^{2} + 4 x + 4}

Factor

x^{2} + 4 x + 4 : (x + 2)^{2}

= \frac{2 ( x + 2 ) ^{3}}{( x + 2 ) ^{2}}

Cancel

\frac{2 ( x + 2 ) ^{3}}{( x + 2 ) ^{2}} : 2 (x + 2)

= 2 (x + 2)

Apply the distributive law:

a (b + c) = ab + a c

a = 2, b = x, c = 2

= 2 x + 2 \cdot 2

Multiply the numbers:

2 \cdot 2 = 4

= 2 x + 4

\frac{1}{x ( 200 - x )}

\frac{124 ! 2 !}{( 124 - 1 ) !}

\frac{d}{df} ((s) (\frac{4 d}{s ^{3}} - \frac{9 x}{s ^{5}}))

u y^{2} (u d y + y d u)

1 0^{30} (y^{30} + 2729079 y^{20}) d y

What is expand (8x^3+48x^2+96x+64)/(4x^2+16x+16) ?
The solution to expand (8x^3+48x^2+96x+64)/(4x^2+16x+16) is 2x+4