What is expand 1/3 (-1)^3+1/2 (-1)^2-2(-1) ?

The solution to expand 1/3 (-1)^3+1/2 (-1)^2-2(-1) is 13/6

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expand 1/3 (-1)^3+1/2 (-1)^2-2(-1)

expand

\frac{1}{3} (- 1)^{3} + \frac{1}{2} (- 1)^{2} - 2 (- 1)

\frac{13}{6}

Decimal Notation

2.16666 \dots

Solution steps

\frac{1}{3} (- 1)^{3} + \frac{1}{2} (- 1)^{2} - 2 (- 1)

Apply rule

- (- a) = a

= \frac{1}{3} (- 1)^{3} + \frac{1}{2} (- 1)^{2} + 2 \cdot 1

\frac{1}{3} (- 1)^{3} = - \frac{1}{3}

= - \frac{1}{3} + (- 1)^{2} \frac{1}{2} + 2 \cdot 1

\frac{1}{2} (- 1)^{2} = \frac{1}{2}

2 \cdot 1 = 2

= - \frac{1}{3} + \frac{1}{2} + 2

Convert element to fraction:

2 = \frac{2}{1}

= \frac{2}{1} - \frac{1}{3} + \frac{1}{2}

Least Common Multiplier of

1, 3, 2 : 6

Adjust Fractions based on the LCM

= \frac{12}{6} - \frac{2}{6} + \frac{3}{6}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{12 - 2 + 3}{6}

Add/Subtract the numbers:

12 - 2 + 3 = 13

= \frac{13}{6}

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What is expand 1/3 (-1)^3+1/2 (-1)^2-2(-1) ?
The solution to expand 1/3 (-1)^3+1/2 (-1)^2-2(-1) is 13/6