What is expand (e^{x+y}+ye^y)+(xe^y-1)(dy)/(dx) ?

The solution to expand (e^{x+y}+ye^y)+(xe^y-1)(dy)/(dx) is e^{x+y}+ye^y+e^yx(dy)/(dx)-(dy)/(dx)

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expand (e^{x+y}+ye^y)+(xe^y-1)(dy)/(dx)

expand

(e^{x + y} + y e^{y}) + (x e^{y} - 1) \frac{d y}{d x}

e^{x + y} + y e^{y} + e^{y} x \frac{d y}{d x} - \frac{d y}{d x}

Solution steps

(e^{x + y} + y e^{y}) + (x e^{y} - 1) \frac{d y}{d x}

= (e^{x + y} + e^{y} y) + (e^{y} x - 1) \frac{d y}{d x}

Expand

\frac{d y}{d x} (x e^{y} - 1) : e^{y} x \frac{d y}{d x} - \frac{d y}{d x}

= (e^{x + y} + y e^{y}) + e^{y} x \frac{d y}{d x} - \frac{d y}{d x}

Remove parentheses:

(a) = a

= e^{x + y} + y e^{y} + e^{y} x \frac{d y}{d x} - \frac{d y}{d x}

\frac{( ( 3 x - 4 ) ^{3} )}{( 2 x + 7 ) ^{2}}

2 (y - 4) e^{2}

\frac{2 ( Ks + I )}{s ( 5 s + 1 ) + 1.96 ( Ks + I )}

3 sec^{2} (\frac{π}{9})

e^{5 x} \cdot (x^{5} e^{5 x} + e^{5 x})

What is expand (e^{x+y}+ye^y)+(xe^y-1)(dy)/(dx) ?
The solution to expand (e^{x+y}+ye^y)+(xe^y-1)(dy)/(dx) is e^{x+y}+ye^y+e^yx(dy)/(dx)-(dy)/(dx)