What are the solutions to the equation d^2=-5 ?

The solutions to the equation d^2=-5 are d=sqrt(5)i,d=-sqrt(5)i

Find the zeros of d^2=-5

The zeros of d^2=-5 are d=sqrt(5)i,d=-sqrt(5)i

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d^{2} = - 5

d = 5 i, d = - 5 i

Solution steps

d^{2} = - 5

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

d = - 5, d = - - 5

- 5 = 5 i

- - 5 = - 5 i

d = 5 i, d = - 5 i

8 x^{3} y^{3} + 27

(6 x^{2} - 7 x - 3) (x + 2) \geq 0

- x^{2} - x + 11 = 0

10 x^{2} = 13 x - 4

What are the solutions to the equation d^2=-5 ?
The solutions to the equation d^2=-5 are d=sqrt(5)i,d=-sqrt(5)i
Find the zeros of d^2=-5
The zeros of d^2=-5 are d=sqrt(5)i,d=-sqrt(5)i