What is expand 7/((s+2)(s+1)(s+4)) ?

The solution to expand 7/((s+2)(s+1)(s+4)) is 7/(s^3+7s^2+14s+8)

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expand 7/((s+2)(s+1)(s+4))

expand

\frac{7}{( s + 2 ) ( s + 1 ) ( s + 4 )}

\frac{7}{s ^{3} + 7 s ^{2} + 14 s + 8}

Solution steps

\frac{7}{( s + 2 ) ( s + 1 ) ( s + 4 )}

Expand

(s + 2) (s + 1) (s + 4) : s^{3} + 7 s^{2} + 14 s + 8

= \frac{7}{s ^{3} + 7 s ^{2} + 14 s + 8}

\frac{2 + 3 s}{s ( s + 2.5 )} + 1

\frac{s - 9}{( s - 1 ) ( s - 5 )}

x^{\frac{3}{2}} (1 - (\frac{1}{2}) ln (x))

\frac{\partial}{\partial y} ((z) (2 - 2 x - 4 y))

\frac{y ^{2} ( - y ^{2} + 1 )}{2}

What is expand 7/((s+2)(s+1)(s+4)) ?
The solution to expand 7/((s+2)(s+1)(s+4)) is 7/(s^3+7s^2+14s+8)