What is expand 16x-(x^2(pi+4))/8 ?

The solution to expand 16x-(x^2(pi+4))/8 is 16x-(pix^2)/8-(x^2)/2

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expand 16x-(x^2(pi+4))/8

expand

16 x - \frac{x ^{2} ( π + 4 )}{8}

16 x - \frac{π x ^{2}}{8} - \frac{x ^{2}}{2}

Solution steps

16 x - \frac{x ^{2} ( π + 4 )}{8}

Expand

x^{2} (π + 4) : π x^{2} + 4 x^{2}

= 16 x - \frac{π x ^{2} + 4 x ^{2}}{8}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{π x ^{2} + 4 x ^{2}}{8} = - (\frac{π x ^{2}}{8}) - (\frac{4 x ^{2}}{8})

= 16 x - (\frac{π x ^{2}}{8}) - (\frac{4 x ^{2}}{8})

Remove parentheses:

(a) = a

= 16 x - \frac{π x ^{2}}{8} - \frac{4 x ^{2}}{8}

Cancel

\frac{4 x ^{2}}{8} : \frac{x ^{2}}{2}

= 16 x - \frac{π x ^{2}}{8} - \frac{x ^{2}}{2}

(\cdot + 10) \cdot (x - 10)

\frac{x ^{3} ( y - 2 )}{e}

\frac{( ( k + 1 ) + 1 ) ( 2 ( k + 1 ) + 1 ) ( 2 ( k + 1 ) + 3 )}{3}

π (2 - 2 q) (1 - π) (2 + p - q)

cosh (0)

What is expand 16x-(x^2(pi+4))/8 ?
The solution to expand 16x-(x^2(pi+4))/8 is 16x-(pix^2)/8-(x^2)/2