What is expand (y^2+ty^2)y'(t)+t^{2-yt^2} ?

The solution to expand (y^2+ty^2)y'(t)+t^{2-yt^2} is y'(t)y^2+ty'(t)y^2+t^{2-yt^2}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand (y^2+ty^2)y'(t)+t^{2-yt^2}

expand

(y^{2} + t y^{2}) y^{'} (t) + t^{2 - y t^{2}}

y' (t) y^{2} + t y' (t) y^{2} + t^{2 - y t^{2}}

Solution steps

(y^{2} + t y^{2}) y^{'} (t) + t^{2 - y t^{2}}

= (y^{2} + t y^{2}) y^{^{'}} (t) + t^{2 - t^{2} y}

Expand

y^{'} (t) (y^{2} + t y^{2}) : y^{'} (t) y^{2} + t y^{'} (t) y^{2}

= y^{'} (t) y^{2} + t y^{'} (t) y^{2} + t^{2 - y t^{2}}

\frac{d ^{2}}{d t ^{2}} ((v (t)) (2 t^{2} + 4 t + 12))

\frac{k ( s + 20 )}{s ( s + 2 ) \cdot ( s + 3 )}

(200 g) (\frac{4.182 J}{( g ^{\circ} C )}) (36. 9^{\circ} C - 23. 8^{\circ} C)

\frac{( - x ^{2} + 12 x - 27 )}{( - x + 6 ) ^{2}}

\frac{d}{d t} ((z (t)) ln (1 + t + (1 + t)^{2}))

What is expand (y^2+ty^2)y'(t)+t^{2-yt^2} ?
The solution to expand (y^2+ty^2)y'(t)+t^{2-yt^2} is y'(t)y^2+ty'(t)y^2+t^{2-yt^2}