What is expand (x+y+3z=8,)*(2x+3y+z=12) ?

The solution to expand (x+y+3z=8,)*(2x+3y+z=12) is 2x^2+3xy+xz=12

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expand (x+y+3z=8,)*(2x+3y+z=12)

expand

(x + y + 3 z = 8,) \cdot (2 x + 3 y + z = 12)

2 x^{2} + 3 x y + x z = 12

Solution steps

(x + y + 3 z = 8,) (2 x + 3 y + z = 12)

= (x + y + 3 \cdot 8 =, z) (2 x + 3 y + 12 = z)

Distribute parentheses

x \cdot 2 x + x \cdot 3 y + x z = 12 + y \cdot 2 x + y \cdot 3 y + yz = 12 + 3 z = 8, 2 x + 3 z = 8, 3 y + 3 z = 8, z = 12

2 xx + 3 x y + x z = 12 + 2 x y + 3 yy + yz = 12 + 3 z = 8, 2 x + 3 z = 8, 3 y + 3 z = 8, z = 12

Expand

2 xx + 3 x y + x z : 2 x^{2} + 3 x y + x z

2 x^{2} + 3 x y + x z = 12

\frac{sec ^{2} ( x ) ( 1 + x ) - tan ( x )}{( 1 + x ) ^{2}}

\frac{( 2 - 3 x ) ^{3}}{( 3 + 2 x ) ^{2}}

\frac{a}{x ( x + a )}

\frac{1}{2 ( p - 12 )}

(c + v^{- 2 t} - 4 e^{t - 2 x})^{2}

What is expand (x+y+3z=8,)*(2x+3y+z=12) ?
The solution to expand (x+y+3z=8,)*(2x+3y+z=12) is 2x^2+3xy+xz=12