What is expand Li+a((d_{1})/(d_{1)+d_{2}}) ?

The solution to expand Li+a((d_{1})/(d_{1)+d_{2}}) is iL+(ad_{1})/(d_{1)+d_{2}}

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expand Li+a((d_{1})/(d_{1)+d_{2}})

expand

L i + a (\frac{d _{1}}{d _{1} + d _{2}})

i L + \frac{a d _{1}}{d _{1} + d _{2}}

Solution steps

L i + a (\frac{d _{1}}{d _{1} + d _{2}})

Remove parentheses:

(a) = a

= L i + a \frac{d _{1}}{d _{1} + d _{2}}

Multiply

a \frac{d _{1}}{d _{1} + d _{2}} : \frac{a d _{1}}{d _{1} + d _{2}}

= i L + \frac{a d _{1}}{d _{1} + d _{2}}

\frac{a - b}{b - a ( b - a )}

\frac{1}{x ^{2} ( x + 2 ) ^{2}}

v - 2 u (2, - 1, 5) - 2 (- 1, 0, 1)

\frac{4 ( y - x \frac{d y}{d x} )}{7 y ^{2}}

\frac{x ^{10}}{( x + a ) ^{5}}

What is expand Li+a((d_{1})/(d_{1)+d_{2}}) ?
The solution to expand Li+a((d_{1})/(d_{1)+d_{2}}) is iL+(ad_{1})/(d_{1)+d_{2}}