What is expand (-2x^2-12)/((x^2-4)^2) ?

The solution to expand (-2x^2-12)/((x^2-4)^2) is (-2x^2-12)/(x^4-8x^2+16)

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expand (-2x^2-12)/((x^2-4)^2)

expand

\frac{- 2 x ^{2} - 12}{( x ^{2} - 4 ) ^{2}}

\frac{- 2 x ^{2} - 12}{x ^{4} - 8 x ^{2} + 16}

Solution steps

\frac{- 2 x ^{2} - 12}{( x ^{2} - 4 ) ^{2}}

(x^{2} - 4)^{2} = x^{4} - 8 x^{2} + 16

= \frac{- 2 x ^{2} - 12}{x ^{4} - 8 x ^{2} + 16}

\frac{1}{( 2 s + 1 ) ^{2}}

x ((x + 3) (x - 3))

\frac{( ( y - 2 x ) ^{(3)} )}{( 4 x + 6 y )}

(t I - t^{2} J + (t - 1) K,) (2 r^{2} I + 6 rK)

e^{x (n + 1)}

What is expand (-2x^2-12)/((x^2-4)^2) ?
The solution to expand (-2x^2-12)/((x^2-4)^2) is (-2x^2-12)/(x^4-8x^2+16)