What is expand (4ln(3))/2 (-)-1/4 (2^2-4+2ln|2+1|-3) ?

The solution to expand (4ln(3))/2 (-)-1/4 (2^2-4+2ln|2+1|-3) is (4ln(3))/2 (-)+3/4-(ln(3))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand (4ln(3))/2 (-)-1/4 (2^2-4+2ln|2+1|-3)

expand

\frac{4 ln ( 3 )}{2} (-) - \frac{1}{4} (2^{2} - 4 + 2 ln ∣ 2 + 1 ∣ - 3)

\frac{4 ln ( 3 )}{2} (-) + \frac{3}{4} - \frac{ln ( 3 )}{2}

Solution steps

\frac{4 ln ( 3 )}{2} (-) - \frac{1}{4} (2^{2} - 4 + 2 ln ∣ 2 + 1 ∣ - 3)

Expand

- \frac{1}{4} (2^{2} - 4 + 2 ln ∣ 2 + 1 ∣ - 3) : \frac{3}{4} - \frac{ln ( 3 )}{2}

= \frac{4 ln ( 3 )}{2} (-) + \frac{3}{4} - \frac{ln ( 3 )}{2}

\frac{7 x + 12}{x ( x + 2 )}

(x - 1) e^{c}

- 25 - (- \frac{96}{- 6} - 27) - (- 3)^{2 \circ} 5

x^{(a - b) \cdot (a + b) \cdot (b - c) \cdot (b + c) \cdot (c - a) \cdot (c + a)}

\frac{( x + 4 ) ( 81 + 6 x )}{x}

What is expand (4ln(3))/2 (-)-1/4 (2^2-4+2ln|2+1|-3) ?
The solution to expand (4ln(3))/2 (-)-1/4 (2^2-4+2ln|2+1|-3) is (4ln(3))/2 (-)+3/4-(ln(3))/2